Correct Answer - Option 4 : 22.5
Given:
Raksha completes work in 27days.
Esther completes work in 45days.
Raksha leaves 9 days before the work is over.
Formula Used:
Efficiency = total work / time taken
Total work = LCM of time taken
Calculation:
Total work = LCM of time taken
⇒ Total work = LCM of 27days and 45 days.
⇒ Total work = 135units.
⇒ Efficiency(Raksha) = 135 / 27 = 5
⇒ Efficiency(Esther) = 135/45 = 3
Efficiency |
Subject |
Time taken |
Total work |
5 |
Raksha |
27 |
135 |
3 |
Esther |
45 |
135 |
Raksha leaves 9 days before the work is over.
last 9 days Esther alone worked.
⇒ Total units of work completed by Esther in 9days
⇒ 9× 3 = 27 units
units of work completed by Raksha and Esther together,
⇒ 135 - 27 = 108 units
108 units of work completed by Raksha and Esther together,
⇒ Time taken by Raksha and Esther together = 108/8
⇒ Time taken by Raksha and Esther together = 13.5 days.
⇒ Esther worked for 13.5days + 9days = 22.5days
∴ Esther works for 22.5 days.