LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
556 views
in Physics by (117k points)
closed by
A 60 W light bulb has a current of 0.5 A flowing through it. Calculate the number of electrons passing through a cross-section of the filament.
1. ≈ 3.1 × 10-18 electrons / min
2. ≈ 3.1 × 1018 electrons / s
3. ≈ 3.1 × 10-18 electrons / s
4. ≈ 3.1 × 1018 electrons / min

1 Answer

0 votes
by (59.8k points)
selected by
 
Best answer
Correct Answer - Option 2 : ≈ 3.1 × 1018 electrons / s

Concept:

Electric current: It defined as the flow of electrons in a wire or rate of flow of charge in a conductor.

The formula for current is I = Q / t

Where Q = charge in Coloumb

t = time in second

Calculation:

Current carried by bulb(I) = 0.5 A

For t = 1 second

Q = I × t = 0.5 C

1 electron has a charge of 1.6 × 10-19 C

For 0.5 C number of electrons passing through a cross-section of the filament is given as

\(\frac{{0.5}}{{1.6 \times {{10}^{ - 19}}}} = 3.125 \times {10^{18}}\) electrons / s

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...