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Shikhar travelled from Prayagraj to Lucknow and covered distance of 200 kms. between the two cities. The first quarter of the journey at a constant speed of 40 km/h and the remaining three quarters at a constant speed of x km/h. If the Average Speed of the person is 53.33 km/h. What is the value of x.
1. 58 km/h
2. 55 km/h
3. 60 km/h
4. 59 km/h
5. 57Km/h

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Best answer
Correct Answer - Option 3 : 60 km/h

Given:

Distance between Prayagraj And Lucknow is 200 kms.

Speed for first quarter of journey = 40 km/h

Speed for remaining three quarter of journey = x km/h

Average Speed of the entire Journey = 53.33 km/h

Formula Used:

\({\rm{Time}} = \frac{{{\rm{Distance}}}}{{{\rm{Speed}}}}\)

Calculation:

If total distance is 200 kms. then each quarter consists of distance of 50 kms.

We can equate the time taken with partial journey speed and average speed journey.

\({\rm{Total\;time\;taken}} = \frac{{50}}{{40}} + \frac{{150}}{x} = \frac{{200}}{{53.33}}\)

\( \Rightarrow \frac{{50{\rm{x}} + 6000}}{{40{\rm{x}}}} = \frac{{200}}{{53.33}}\)

\( \Rightarrow \left( {50{\rm{x}} + 6000} \right) \times 53\frac{1}{3}\; = 200 \times 40{\rm{x}}\)

\( \Rightarrow \left( {50{\rm{x}} + 6000} \right) \times \frac{{160}}{3} = 8000x\)

⇒ (8000x + 960000) = 24000x

⇒ 16000x = 960000

\( \Rightarrow {\rm{x}} = \frac{{960000}}{{16000}} = 60\)

∴ Value of x is 60 km/h.

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