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A and B are friends and A is 2 years older than B. A's father D is twice as old as A and B's age is twice as old as his sister C's age. The difference between D and C's age is 40 years. Find the age of A.
1. 25 years
2. 15 years
3. 40 years
4. 26 years

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Correct Answer - Option 4 : 26 years

Given:

D – C = 40 years.

Calculation:

According to problem

D – C = 40

⇒ C = D – 40      ----1

B's age is twice as old as his sister C's age

B = 2(D - 40)      ----2

A is 2 years older than B

A = 2(D - 40) + 2      ----3

D is twice as old as A 

D = 2A      ----4

⇒ D = 2(2(D - 40) + 2)

⇒ D = 4D -160 + 4

⇒ 3D = 156

⇒ D = 52 years

From equation 4

⇒ A = 52/2 = 26

∴ Age of age is 26 years

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