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Mrinalini and Samyukta can work together to paint half of a wall in 14 days. Working separately, Mrinalini would need four times the time taken by the Samyukta to complete it. In how many days can the Samyukta paint the entire wall alone?


1. 30
2. 28
3. 42
4. 35

1 Answer

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Best answer
Correct Answer - Option 4 : 35

Given :

Mrinalini and Samyukta can paint half of the wall in 14 days

Mrinalini need 4 times more time than Samyukta 

Concept used :

Working efficiency is inversely proportional to time taken 

Total work = person's efficiency × Number of days he takes for work 

Calculations :

Half the work will be completed in 14 days 

Full work will be completed in 28 days 

Total work = 28 units 

Now,

Let the efficiency of Mrinalini be 'x' unit per day 

So the efficiency of Samyukta will be '4x'  per day 

Mrinalini and Samyukta per day work = x + 4x = 5x units 

So,

(5x) × 28 = 28 units 

⇒ 5x = 28 /28

⇒ x = 1/5 units 

Samyukta's per day work = 4x 

⇒ 4 × (1/5) = 4/5 units 

Total days of working of Samyukta = 28/(4/5) 

⇒ 35 days 

∴ Samyukta will complete the work in 35 days 

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