LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
153 views
in Mathematics by (117k points)
closed by
A can do a job alone in 24 days. B is 50% more efficient than A. Then B alone can finish the job in
1. 12 days
2. 18 days
3. 10 days
4. 16 days

1 Answer

0 votes
by (59.9k points)
selected by
 
Best answer
Correct Answer - Option 4 : 16 days

Given:

A can do a job = 24 days

B's efficiency = 50% more than A

Concept used:

The efficiency of work done is always inversely proportional to the time taken to do the work

Formula used:

Time is taken = Total work/Efficiency

Calculations:

Let the efficiency of A = 100%

Then, the efficiency of B = 100% + 50%

⇒ 150%

The ratio of efficiencies of A and B = 100% ∶ 150%

⇒ 2 ∶ 3

The ratio of number of days taken to complete work by A and B = 3 ∶ 2

Number of days taken to complete by B = (24/3) × 2

⇒ 16 days

∴ B alone can finish the job in 16 days

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...