Correct Answer - Option 2 : 0
Concept:
The difference of any three-digit number by its reversing number is always an exact product of 9 So, it is divisible by 9.
Calculation:
Let 100x + 10y + z be the number its reverse is 100z + 10y + x
Difference of the number will be
⇒ (100z + 10y + x) − (100x + 10y + z)
⇒ (100 − 1)z + (10 − 10)y + (1 − 100)x
⇒ 99z − 99x = 99(z − x)
So the difference of any three-digit number with its reverse number is divisible by 9 then the remainder is 0
∴ Remainder is 0