Correct Answer - Option 2 : bbcd
The given series:
a _ cd _ cda _ dab _ abc
a |
c |
c |
d |
d |
c |
d |
a |
b |
d |
a |
b |
b |
a |
b |
c |
a |
b |
c |
d |
b |
c |
d |
a |
c |
d |
a |
b |
d |
a |
b |
c |
a |
b |
c |
d |
c |
c |
d |
a |
d |
d |
a |
b |
b |
a |
b |
c |
a |
b |
c |
d |
c |
c |
d |
a |
d |
d |
a |
b |
d |
a |
b |
c |
There are 16 terms in the series with four different letters being repeated, which implies a pattern of 4 letters.
In option 2, there is a pattern formation of cyclic repeating letters starting from the next letters.
⇒ abcd / bcda / cdab / dabc
First group four letters start with a
Second group four letters start with b
Third group four letters start with c
Fourth group four letters start with d
Hence, 'bbcd' will replace the blanks in the given series.