Correct Answer - Option 3 : x = y or relation between x and y can't be established
From I,
x2 – 6x + 8 = 0
⇒ x2 – 4x – 2x + 8 = 0
⇒ (x – 4)(x – 2) = 0
⇒ x = 4, 2
From II,
4y2 – 24y + 32 = 0
⇒ 4y2 - 16y - 8y + 32 = 0
⇒ (y - 4)(4y – 8) = 0
⇒ y = 4, 2
Comparison between x and y (via Tabulation):
Value of x
|
Value of y
|
Relation
|
4
|
4
|
x = y
|
4
|
2
|
x > y
|
2
|
4
|
x < y
|
2
|
2
|
x = y
|
∴ Relation between x and y can't be established.