Correct Answer - Option 1 : x < y

**Calculation:**

**From I,**

5x^{2} + 3x – 14 = 0

⇒ 5x^{2} + 10x – 7x – 14 = 0

⇒ 5x(x + 2) –7(x +2) = 0

⇒ (5x–7) (x+2) = 0

Taking

⇒5x – 7 = 0 or x + 2 = 0

⇒ x = 7/5 or x = –2

**From II,**

y^{2}– 41y + 180 = 0

⇒ y^{2}– 36y – 5y +180 = 0

⇒ y(y–36) – 5(y–36) = 0

⇒ (y–5) (y–36) = 0

Taking,

⇒ y – 5 = 0 or y – 36 = 0

⇒ y = 5 or y = 36

**Values of x** |
**Values of y** |
**Relation** |

7/5 |
5 |
x < y |

–2 |
5 |
x < y |

7/5 |
36 |
x < y |

–2 |
36 |
x < y |

**∴ The relation between x and y is, x < y.**