Question

In the given question, two equations numbered l and II are given. Solve both the equations and
mark the appropriate answer.

I.7x² + 32x – 15 = 0

II. 4y²– 16y +7 = 0

1. x > y
2. x < y
3. x ≤ y
4. x ≥ y
5. x = y or the relationship between x and y cannot be established.

Answer 1

Correct Answer - Option 2 : x < y

Calculation:

From I,

7x² + 32x – 15 = 0

⇒ 7x² + 35x – 3x – 15x = 0

⇒ 7x(x+5) – 3(x+5) = 0

⇒ (7x–3) (x+5) = 0

Taking,

⇒ 7x – 3 = 0 or x + 5 = 0

⇒ x = 3/7 or –5

From II,

4y²– 16y + 7 = 0

⇒ 4y²– 14y - 2y + 7 = 0

⇒ 2y(2y–1) –7(2y-1) = 0 

⇒ (2y–1) (2y–7) = 0

Taking, 

⇒ 2y – 1 = 0 or 2y – 7 = 0

⇒ y = 1/2 or y = 7/2

 

Values of x	Values of y	Relation
3/7	1/2	x < y
–5	1/2	x < y
3/7	7/2	x < y
–5	7/2	x < y

 

∴ Relation between x and y is, x < y.