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A cricket ball of mass 150 g is moving with a velocity of 12 m / s and is hit by a bat so that the ball is turned back with a velocity of 20 m / s. If the duration of contact between the ball and the bat is 0.01 sec. The impulse of the force is:
1. 4.8 N-S
2. 7.4 N-S
3. 1.2 N-S
4. 4.7 N-S

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Correct Answer - Option 1 : 4.8 N-S

Concept:

Impulse

  • When a large force works on a body for a very small time interval, it is called impulsive force.
  • An impulsive force does not remain constant, but changes first from zero to maximum and then from maximum to zero. In such case, we measure the total effect of force.
  • The impulse caused by a force during a specific time interval is equal to the body's change of momentum during that time interval.
  • Impulse, effectively, is a measure of change in momentum.
  • Impulse of a force is a measure of the total effect of force.
  • Impulse is a vector quantity and its direction is same as that of force.
  • SI unit of impulse is Newton-second or kg-m-s-1.

\(\vec I = \mathop \smallint \nolimits_{{t_1}}^{{t_2}} \overrightarrow {F\;} \cdot dt\)

Where, I = impulse, F = force and dt = very small time interval

Hence according to given explanation above

  • Impulse, \(I=~\int \frac{dp}{dt}.dt⇒ i.e.,~I=\left( {{p}_{2}}-{{p}_{1}} \right)=\text{ }\!\!Δ\!\!\text{ }p\)
  • therefore we can say that impulse is equals to change in momentum

Calculation:

Mass of the ball (m) = 150 g = 0.15 kg

Initial velocity (u) = 12 m/s

Final velocity (v) = 20 m/s

Time = 0.01 s

Initial Momentum p1 = 0.15 × (-12) = -1.8 kg m/s

Final Momentum p2 = 0.15 kg × 20 = 3 kg m/s

Impulse = F × T = change of momentum

⇒ F × T = p2 - p1 = (3 - (-1.8)) = 4.8 

⇒ F × 0.01 = 4.8

⇒ F = 480 N -s

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