Correct Answer - Option 3 : 2.5 poise
Concept:
According to Newton’s law of viscosity, \(τ = μ \frac{{du}}{{dy}}\) the shear stress is directly proportional to the rate of shear strain or the rate of angular deformation of a fluid particle. The fluid-particle tends to deform continuously when it is in motion.
\(τ = μ \frac{{du}}{{dy}}\)
Newton’s law of viscosity is a relationship between shear stress and the rate of shear strain.
Calculation:
Given:
τ = 0.05 N/m2, du/dy= 0.2 s-1, Viscosity, μ = ?
\(τ = μ \frac{{du}}{{dy}}\)
\(0.05 = \mu \times 0.2= 0.25 \frac{Ns}{m^2}=2.5 ~poise\)