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A bullet of mass 50 g is horizontally fired with velocity 100 ms-1 from a pistol of mass 10 kg. Total momentum of the pistol and bullet before firing is equal to
1. 0.5 ms-1.
2. 201.5 ms-1
3. 215  ms-1
4. 200  ms-1

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Correct Answer - Option 1 : 0.5 ms-1.

The correct answer is 0.5 ms-1.

  • By momentum conservation
  • mBVB = mGvG = 0
  • Recoil velocity vG = −VBmB/ mG
  • vG = −(50*1000*100)/10
  • vG = 0.5m/s.

  • SI unit of momentum is a kilogram - meter per second.
    • The units of momentum will be the product of the units of mass and velocity.
    • Mass is measured in kg and velocity in ms-1.
    • Therefore, the SI unit of momentum will be kgm/s.
  • Newton - meter per second:
  • when force is equivalent to the rate of change of momentum -
    •  Force = (change in momentum)/(time interval) then, change in momentum = Force x (time interval).
    • Therefore, the unit for momentum can be Newton-second (Ns)
  • Gram - centimetre per second:
    •  If the mass is in grams and the velocity is in centimetres per second, then the unit of momentum will be gram-centimetres per second (g⋅cm/s).
  • Joule - metre per second:
    • The joule-second is a unit of action or of angular momentum.
    • The joule-second (symbol J⋅s.) is the product of an SI derived unit, the joule (J), and an SI base unit, the second (s).

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