Correct Answer - Option 4 : 1.2
Concept:
Emf induced in a DC generator is directly proportional to Flux per pole and the rotor speed i.e.
E ∝ ϕ ⋅ ω
or. E = Ka ϕ ⋅ ω
Where Ka = Proportionality constant \(=\frac{ZP}{2\pi A}\)
Where, Z = No. of conductors
P = No. of Poles
A = No. of Parallel paths
ϕ = Flux per pole
ω = Angular velocity in rad/sec
Converting it in rotation per minute,
\(\omega = \frac{2\pi N}{60}\)
By Putting the above values in EMF equation, we will get
\(E=\frac{ϕ ZN}{60}\times \frac{P}{A}\)
Calculation:
Given,
P = 4, N = 650 rpm
E = 200 V, Z = 750
A = 2, ϕ = 0.015 wb
\(E = \frac{\phi Z N}{60}\times \frac{P}{A}\)
\(E=\frac{0.015 \times 750 \times 650}{60} \times \frac{4}{2}\)
E = 243.75 V
Given, generation rating of convertor is 200.
But it is generating 243.75 V
Hence, leakage coefficient \(=\frac{243.75}{200}\)
= 1.21875
Hence, correct option will be option (4)
No. of parallel paths in wave wound machine = 2
No. of parallel paths in lap wound machine = No. of poles i.e. A = P