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In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. 5x2 - 14x -3 = 0

II. 9y2 + 16y - 4 = 0


1. y ≤ x
2. y ≥ x
3. y > x
4. y < x
5. x = y 0r no relation cannot be established

1 Answer

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Best answer
Correct Answer - Option 5 : x = y 0r no relation cannot be established

I. 5x2 - 14x -3 = 0

⇒ 5x2 -15x + x - 3 =0

⇒ 5x( x - 3) + 1(x -3) = 0 

⇒ (5x +1)(x -3) = 0

⇒ x = -1/5, 3

II. 9y2 + 16y - 4 = 0

⇒ 9y2 -18y + 2y - 4 =0

⇒ 9y( y - 2) + 2(y -2) = 0 

⇒ (9y + 2)(y - 2) = 0

⇒ y = -2/9, 2

 

value of x value of y relation x,y
  -1/5   -2/9  x > y
  3  2  x > y
 -1/5  2  x< y
  3  -2/9  x > y

 

∴ No relation can established between x,y

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