Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
704 views
in Reasoning by (238k points)
closed by
Four players A, B, C, and D have to form into two pairs, however, no pair can play together more than seven times in a row A and B have played seven games in a row. C and D have three in a row. C does not to work with A. Who should play with B?
1. A
2. D
3. C
4. Cannot be determined

1 Answer

0 votes
by (240k points)
selected by
 
Best answer
Correct Answer - Option 4 : Cannot be determined

Given:

Four players A, B, C, and D have to form into two pairs.

No pair can play together more than seven times in a row.

A and B have played seven games in a row.

C and D have three in a row.

C does not work with A.

Then, C and D can still play 4 times.

B either will play with C or D.

Hence, it cannot be determined exactly.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...