Question

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. 3x² + 19x + 20 = 0

II. 6y² + 19y +15 = 0

1. x ˃ y
2. x ˂ y
3. x ≥ y
4. x ≤ y
5. x = y or the relationship between x and y cannot be established.

Answer 1

Correct Answer - Option 5 : x = y or the relationship between x and y cannot be established.

From equation I) we get,

3x² + 19x + 20 = 0

⇒  3x² + 15x+ 4x + 20 = 0

⇒ 3x (x+ 5) + 4(x+5) + 20 = 0

⇒ (x+5) (3x + 4) = 0

∴ x = -5, - 4/3

From equation II) we get,

6y² + 19y + 15 = 0

⇒ 6y² + 10y + 9y + 15 = 0

⇒ 2y (3y + 5) + 3(3y + 5) = 0

⇒ (2y + 3) (3y + 5) = 0

∴  y = -3/2, -5/3

Comparison between x and y (via Tabulation):

Value of x	Value of y	Relation
-5	-3/2	x < y
-5	-5/3	x < y
-4/3	-3/2	x > y
-4/3	-5/3	x > y

 

∴ The relationship between x and y cannot be established.