Question

When four positive numbers a, b, c, and d are divided by 41, the remainders are 3, 4, 6, and 2, respectively. When (5a + 6b – 2c + 10d) is divided by 41, then, the remainder will be – 
1. 5
2. 7
3. 6
4. 17

Answer 1

Correct Answer - Option 3 : 6

GIVEN:

When four positive numbers a, b, c, and d are divided by 41, the remainders are 3, 4, 6, and 2, respectively.

CONCEPT:

Dividend = Divisor x Quotient + Remainder

CALCULATION:

a = 41w + 3, b = 41x + 4, c = 41y + 6, d = 41z + 2

Here, 41w, 41x, 41y and 41z is divisible by 41.

So, according to question –

(5a + 6b – 2c + 10d)

⇒ (15 + 24 – 12 + 20)

⇒ 59 – 12

⇒ 47

When (5a + 6b – 2c + 10d) is divided by 41.

⇒ Remainder (47/41) = 6