Correct Answer - Option 1 : 543
Given:
The sum of four consecutive odd integers = 2160
Calculations:
Let the first integer be 'n'
The next three odd integers be 'n + 2', 'n + 4' , 'n + 6'
The sum number = n + n + 2 + n + 4 + n + 6
⇒ 4n + 12
4n + 12 = 2160
⇒ 4(n + 3) = 2160
⇒ (n + 3) = 2160/4
⇒ n = 540 - 3 = 537
The greatest number n + 6 = 537 + 6
⇒ 543
∴ The greatest of them is 543