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The diameter of a metal rod is 4 cm. Find the stress produced in N/mm2 if 2200 N weight is applied on it.
1. 175
2. 5.5
3. 17.5
4. 1.75

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Correct Answer - Option 4 : 1.75

Concept:

Stress in axial loading is given by;

\(σ=\frac{F}{A}\)

where σ = Normal stress, F = Load/Weight, A = Area of cross-section

\(A=\frac{\pi d^2}{4}\)

where d = Diameter

Calculation:

Given:

F = 2200 N, d = 4 cm = 40 mm

\(A=\frac{\pi\times (40)^2}{4}=1256.63\ mm^2\)

\(σ=\frac{2200}{1256.63}\)

σ = 1.75 N/mm2 

Hence the stress induced in the metal rod will be 1.75 N/mm2.

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