Correct Answer - Option 3 : 90
Given:
The 11th term of an AP is 90 less than the first term. The second term is 99.
Formula:
nth term of an AP, Tn = a + (n - 1)d, where ‘a’ is the first term, ‘n’ is the total number of terms and ‘d’ is the common difference.
Calculation:
Let the first term is ‘a’ and common difference is‘d’.
T2 = a + d = 99 ----(1)
According to question
T1 - T11 = 90
⇒ a - (a + 10d) = 90
⇒ - 10d = 90
d = - 9
From equation (1)
a + (- 9) = 99
⇒ a = 108
Third term T3 = a + 2d
⇒ 108 + 2 × - 9 = 108 - 18 = 90
∴ Required answer is 90.