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A is twice as efficient as B, who is thrice as efficient as C. If C alone can complete the task in 30 days, then in how many days can they together complete the task?
1. 3
2. 4
3. 5
4. 6

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Correct Answer - Option 1 : 3

Given:

A is twice as efficient as B

B is thrice as efficient as C

C alone can do work in 30 days

Concept Used:

Total work = Time taken × Efficiency

Calculation:

A = 2B

B = 3C

A ∶ B = 2 ∶ 1

B ∶ C = 3 ∶ 1

A ∶ B ∶ C = 6 ∶ 3 ∶ 1

C alone can do work in 30 days

 So, total work = 1 × 30 = 30 units

Efficiency of (A + B + C) = 6 + 3 + 1 ⇒ 10 units

∴ Work completed by A, B and C = 30/10 = 3 days

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