Correct Answer  Option 2 : 156000 J
CONCEPT:

Workenergy theorem: It states that the sum of work done by all the forces acting on a body is equal to the change in the kinetic energy of the body i.e.,
Work done by all the forces = Kf  Ki
\(W = \frac{1}{2}m{v^2}  \frac{1}{2}m{u^2} = {\bf{Δ }}K\)
Where v = final velocity, u = initial velocity and m = mass of the body
CALCULATION:
It is given that,
Initial velocity (u) = 30 km/h = (30 × 1000/3600) = 25/3 m/s
Initial Kinetic energy (KE_{i}) = 52000 = \(\frac{1}{2}mu^2\)
Final Velocity (v) = 60 km/h = (60 × 1000/3600) = 50/3 m/s = 2u
Final kinetic energy (KE_{f}) = \(\frac{1}{2}mv^2 = \frac{1}{2}m (2u)^2 =4 KE_i \)
KE_{f } = 4 × 52000 = 208000 J
According to the workenergy theorem,
⇒ Work done = Change in K.E
⇒ Work done (W) = Δ K.E = KE_{f}  KE_{i} = 208000  52000 = 156000 J