Correct Answer - Option 3 : 70
Concept:
Power gain is the ratio of the output power (P0) to the input power (Pin), i.e.
\({A_p} = \frac{{{P_0}}}{{{P_{in}}}}\)
In terms of dB, the power gain is expressed as:
\(P(dB) = 10\log_{10}{A_p}\) ----(1)
Application:
Given:
Ap = 10,000,000 = 107
From equation (1);
\(P(dB) = 10\log_{10}{10^7}\)
\(P(dB) = 70\log_{10}{10}\)
P(dB) = 70