Correct Answer - Option 4 : 1220
Given
Numbers from 41 to 80
All number between 41 to 80 should be even number
Formula used
Tn = a + (n-1)d
Sn = \(\frac{n}{2}\left\{ {2A + \left( {N - 1} \right)D} \right\}\)
Where, Tn = last number in the series
Sn = Sum of series of AP
N = number of terms in series
A = first number of the series
D = difference of consecutive series
Calculation:
Even number between 41 to 80
⇒ 42, 44, 46, 48, 50 ..............80
⇒ This series is in AP
Where, a = 42
⇒ d = a2 - a1
⇒ 44 - 42 = 2
Tn = a + (n-1)d
⇒ 80 = 42 + (n-1)2
⇒ 38 = (n-1)2
⇒ n = 20
⇒ Sn = \(\frac{{20}}{2}\left\{ {2 × 42 + \left( {20 - 1} \right)2} \right\}\)
⇒ 20{42 + 19}
⇒ 20 × 61
∴ 1220