# If y is the weight of dry steam and x is the weight of water suspension, then dryness fraction is equal to

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If y is the weight of dry steam and x is the weight of water suspension, then dryness fraction is equal to
1. $\frac{x}{y +x}$
2. $\frac{y}{x +y}$
3. $\frac yx$
4. ​​$\frac xy$

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Correct Answer - Option 2 : $\frac{y}{x +y}$

Explanation:

Dryness fraction:

Dryness fraction (x) of steam is defined as the ratio of the mass of the dry steam to the total mass of both dry steam and liquid.

$x = \frac{{{m_g}}}{{{m_f} + {m_g}}}\;\left( {0 \le x \le 1} \right)$

where mg = mass of the dry steam and mf = mass of liquid

Calculation:

Given:

mg = y, mf = x

Dryness fraction = $\frac {m_g}{m_f+m_g} = \frac {y}{x+y}$