LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
25 views
in General by (60.0k points)
closed by

Comprehension

Directions: Study the data in the given table and answer the questions that follow

The table below embodies data on the number of students who appeared (A) and passed (P) in a competitive examination from four different zones (K, L, M and N) during the year 2014 to 2019.

Year

Zone

K

L

M

N

A

P

A

P

A

P

A

P

2014

782

360

612

310

720

410

1020

802

2015

804

472

608

324

728

480

1135

840

2016

720

448

636

298

680

390

1084

864

2017

750

360

655

305

695

396

1096

766

2018

824

504

640

346

712

424

1180

752

2019

850

496

600

315

740

464

1165

780


1. K
2. L
3. M
4. N

1 Answer

0 votes
by (110k points)
selected by
 
Best answer
Correct Answer - Option 2 : L

Formula used:

Percentage of passed student = Passed student/Appeared student × 100 

Calculation:

In Zone-K,

Percentage of passed student in 2019 = 496/850 × 100 = 58.35%

In Zone-L,

Percentage of passed student in 2019 = 315/600 × 100 = 52.5%

In Zone-M,

Percentage of passed student in 2019 = 464/740 × 100 = 62.70%

In Zone-N,

Percentage of passed student in 2019 = 780/1165 × 100 = 66.95%

∴ The minimum passed percentage in 2019 is in Zone-L

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...