Correct Answer - Option 4 : Rank of T = Nullity of T = 2
Concept:
Let V and W be a vector space over F and T: V → W is a linear transformation then null space of T is given by Ker T = {v ∈ V | T(v) = 0 where 0 ∈ W}
So, the nullity of T is the dimension of the null space of T.
Range space of T is given by R(T) = {w ∈ W| T(v) = w fo v ∈ V} and Rank of T is the dimension of R(T)
Rank - Nullity Theorem:
Let T be a linear transformation from V to W i.e T: V → W and V is a finite-dimensional vector space then Rank (T) + Nullity (T) = dim V
Analysis:
Given:
T : R4 → R4
T(x, y, z, u) = (x, y, 0, 0)
Let us first find the dimension of null space (nullty)
Null space of T = kernel of T (ker T)
Ker T = { v ∈ V | T(v) = 0}
Ker T = (0, 0, 0, 0) = (x, y, 0, 0)
x = 0, y = 0
The dimension of Ker T = dimension of basis of Ker T = 2
∴ Nullity = 2
dim (V) = 4
∴ 4 = Nullity + Rank (T)
Rank (T) = 4 – 2 = 2