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The voltage at the two ends of a line are 132 kV and its reactance is 40 ohms. The capacity of the line is
1. 217.8 MW
2. 251.5 MW
3. 435.6 MW
4. 500 MW

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Correct Answer - Option 3 : 435.6 MW

Concept: 

The maximum power transfer capacity of the transmission line is given by

\(P = \frac{{\left| {{V_s}} \right|\left| {{V_r}} \right|}}{X}\)

Where,

|Vs| is sending end voltage of transmission line

|Vr| is receiving end voltage of transmission line

X is the series reactance of transmission line

Calculation:

Given 

Vs = Vr = 132 kV

X = 40 Ω

The capacity of the line P

P = (132 × 103)2 / 40 = 435.6 MW

Therefore, the capacity of the line is 435.6 MW

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