Correct Answer - Option 3 : 435.6 MW
Concept:
The maximum power transfer capacity of the transmission line is given by
\(P = \frac{{\left| {{V_s}} \right|\left| {{V_r}} \right|}}{X}\)
Where,
|Vs| is sending end voltage of transmission line
|Vr| is receiving end voltage of transmission line
X is the series reactance of transmission line
Calculation:
Given
Vs = Vr = 132 kV
X = 40 Ω
The capacity of the line P
P = (132 × 103)2 / 40 = 435.6 MW
Therefore, the capacity of the line is 435.6 MW