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A shaft rotating at 150 rpm is subjected to a torque of 1500 N.m. Horse power transmitted by the shaft is
1. π2 
2. π
3. 10π
4. 1/10π

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Best answer
Correct Answer - Option 3 : 10π

Concept:

Power is given by;

\(% MathType!Translator!2!1!AMS LaTeX.tdl!AMSLaTeX! % MathType!MTEF!2!1!+- % feaagKart1ev2aqatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaaeaaaaaaaaa8 % qacaWGqbGaeyypa0ZaaSaaa8aabaWdbiaaikdacqaHapaCcaWGobGa % amivaaWdaeaapeGaaGOnaiaaicdaaaaaaa!3DDF! P = \frac{{2π NT}}{{60}}\)\(P = \frac{{2\pi NT}}{{60}}\)

Where P is in watt

N = Angular velocity

T = Torque

Calculation:

1 H.P. = 745.7 watt

Given;

N = 150 rpm

T = 1500 N.m

So from the above equation;

\(P = \frac{{2π \times 150 \times 1500}}{{60}}\)

P = 7500π watt

\(P = \frac{{7500π }}{{745.7}}\) H.P.

P = 10π H.P.

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