Question

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

l. 2x² + 23x + 56 = 0

ll. 12y² + 41y + 35 = 0

1. x > y
2. x < y
3. x ≥ y
4. x ≤ y
5. x = y or relation between x and y can not be determined.

Answer 1

Correct Answer - Option 2 : x < y

Calculation:

l. 2x² + 23x + 56 = 0

⇒ 2x² + 16x + 7x + 56 = 0

⇒ 2x(x + 8) + 7(x + 8) = 0

⇒ (2x + 7) (x + 8) = 0

⇒ x = -7/2, -8

ll. 12y² + 41y + 35 = 0

⇒ 12y² + 21y + 20y + 35 = 0

⇒ 3y(4y + 7) + 5(4y + 7) = 0

⇒ (3y + 5) (4y + 7) = 0

⇒ y = -5/3, -7/4

Comparison between x and y (via Tabulation):

Value of x	Value of y	Relation
-7/2	-5/3	x < y
-7/2	-7/4	x < y
-8	-5/3	x < y
-8	-7/4	x < y

∴ The result will be x < y.