Correct Answer - Option 1 :
x > y
Calculation:
l. x2 – 25x + 156 = 0
⇒ x2 – (13 + 12)x + 156 = 0
⇒ x2 – 13x – 12x + 156 = 0
⇒ x(x – 13) – 12(x – 13) = 0
⇒ (x – 13) (x – 12) = 0
⇒ x = 13, 12
II. y2 + 33y + 162 = 0
⇒ y2 + (27 + 6)y + 162 = 0
⇒ y2 + 27y + 6y + 162 = 0
⇒ y(y + 27) + 6(y + 27) = 0
⇒ (y + 27) (y + 6) = 0
⇒ y = -27, -6
Comparison between x and y (via Tabulation):
Value of x
|
Value of y
|
Relation
|
13
|
-27
|
x > y
|
13
|
-6
|
x > y
|
12
|
-27
|
x > y
|
12
|
-6
|
x > y
|
∴ x > y