Correct Answer - Option 3 : x = y or the relationship cannot be established.
I. 4x2 – 72x + 224 = 0
⇒ 4x2 – 56x – 16x + 224 = 0
⇒ 4x(x – 14) – 16(x – 14) = 0
⇒ (x – 14)(4x – 16) = 0
⇒ x = 14 or 4
II. y2 – 19y + 60 = 0
⇒ y2 – 15y – 4y + 60 = 0
⇒ y(y – 15) – 4(y – 15) = 0
⇒ (y – 15)(y – 4) = 0
⇒ y = 15 or 4
Comparison between x and y (via Tabulation):
Value of x
|
Relation
|
Value of y
|
14
|
<
|
15
|
14
|
>
|
4
|
4
|
<
|
15
|
4
|
=
|
4
|
∴ x = y or the relationship cannot be established.