Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
66 views
in Algebra by (240k points)
closed by

 In the given questions, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer

I. 4x2 – 72x + 224 = 0

II. y2 – 19y + 60 = 0


1. x > y
2. x ≤ y
3. x = y or the relationship cannot be established.
4. x ≥ y
5. x < y

1 Answer

0 votes
by (238k points)
selected by
 
Best answer
Correct Answer - Option 3 : x = y or the relationship cannot be established.

I. 4x2 – 72x + 224 = 0

⇒ 4x2 – 56x – 16x + 224 = 0

⇒ 4x(x – 14) – 16(x – 14) = 0

⇒ (x – 14)(4x – 16) = 0

⇒ x = 14 or 4

II. y2 – 19y + 60 = 0

⇒ y2 – 15y – 4y + 60 = 0

⇒ y(y – 15) – 4(y – 15) = 0

⇒ (y – 15)(y – 4) = 0

⇒ y = 15 or 4

Comparison between x and y (via Tabulation):

Value of x

Relation

Value of y

14

15

14

4

4

15

4

=

4

∴ x = y or the relationship cannot be established.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...