Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
70 views
in Statistics by (240k points)
closed by

The runs scored in a cricket match by 11 players are as follows:

16, 9, 15, 18, 50, 100, 102, 14, 20, 80, 5. Let x, y, and z be the range, mean and median respectively of this data. If x = y + z + p, then the value of p is


1. 42
2. 43
3. 58
4. 40

1 Answer

0 votes
by (238k points)
selected by
 
Best answer
Correct Answer - Option 4 : 40

Given:

The runs scored in a cricket match by 11 players as follows

16, 9, 15, 18, 50, 100, 102, 14, 20, 80, 5

Mean of data = y

Range of data = x

Median of data = z

Concept used:

The range is the spread of your data from the lowest to the highest value in the distribution. The range is calculated by subtracting the lowest value from the highest value. 

The mean is the same as the average value of a data set and is found using a calculation. Add up all of the numbers and divide by the number of numbers in the data set.

The median is the middle number in a data set when the numbers are listed in either ascending or descending order. 

Calculations:

Mean y = (16 + 9 + 15 + 18 + 50 + 100 + 102 + 14 + 20 + 80 + 5)/ 11

⇒ 429/11 = 39

The highest value in the given data = 102

The lowest value  in the given data = 5

Range x = 102 - 5

⇒ 97

Now arrange the data in ascending order:

5, 9, 14, 15, 16, 18, 20, 50, 80, 100, 102

⇒ Median = middle value = 18 (Since total numbers are odd)

 x = y + z + p

⇒ 97 = 39 + 18 + p

⇒ p = 97 - 39 - 18

⇒ p = 40

∴ Th required value of p is 40

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...