Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
47 views
in Algebra by (240k points)
closed by

In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I: x2 + 6x – 247 = 0

II: y2 + 27y + 182 = 0


1.

x > y


2.

x ≤ y


3.

x = y or the relationship between x and y cannot be established.


4.

x ≥ y


5. x < y

1 Answer

0 votes
by (238k points)
selected by
 
Best answer
Correct Answer - Option 3 :

x = y or the relationship between x and y cannot be established.


Calculation:

I: x2 + 6x – 247 = 0

⇒ x2 – 13x + 19x – 247 = 0

⇒ x × (x – 13) + 19× (x – 13) = 0

⇒ (x – 13) × (x + 19) = 0

⇒ x = (-19), 13

II: y2 + 27y + 182 = 0

⇒ y2 +14y + 13y + 182 = 0

⇒ y × (y + 14) + 13 × (y + 14) = 0

⇒ (y + 13) × (y + 14) = 0

⇒ y = -14, -13

Comparison between x and y (via Tabulation):

Value of x

relation

Value of y

-19

-14

-19

-13

13

>

-14

13

>

-13

 

∴ x = y or the relationship between x and y cannot be established.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...