A container contains two liquids B1 and B2 in the ratio of 8 ∶ 7. When 15 litres of mixture is removed from the container and is replaced with B2, the

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A container contains two liquids B1 and B2 in the ratio of 8 ∶ 7. When 15 litres of mixture is removed from the container and is replaced with B2, the ratio of B1 and B2 becomes 2 ∶ 3. How many litres of B1 was in the container initially?
1. 40 litres
2. 32 litres
3. 50 litres
4. 60 litres

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Correct Answer - Option 2 : 32 litres

Given:

The contains two liquids are ratio = 8 : 7

Calculation:

Let us assume B1 and B2 is 8x and 7x respectively.

⇒ ${8x\ -\ 8 \over 7x\ -\ 7\ +\ 15}\ =\ {2\over 3}$

⇒ ${8x\ -\ 8\over 7x\ +\ 8}\ =\ {2\over 3}$

⇒ 24x - 24 = 14x + 16

⇒ 24x - 14x = 16 + 24

⇒ 10x = 40

⇒ x = 4

⇒ B1 liquid in container initially = 8x = 8 × 4 = 32 litres

∴ The required result will be 32 litres.

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