Question

24 men can do a work in 10 days while working for 9 hours per day. If they work for 6 hours per day, then in how many days 18 men can do the 2 times of that work?
1. 36 days
2. 40 days
3. 31 days
4. 32 days

Answer 1

Correct Answer - Option 2 : 40 days

Given:

M₁ = 24

D₁ = 10

H₁ = 9

M₂ = 18

H₂ = 6

W₂ = 2 × W₁

Formula Used:

(M₁ × D₁ × H₁)/W₁ = (M₂ × D₂ × H₂)/W₂

Where, M₁ → Initial Men,

D₁ → Initial day

H₁ → Initial hour

M₂ → final men

D₂ → Final day

H₂ → Final hour

Calculation:

(M₁ × D₁ × H₁)/W₁ = (M₂ × D₂ × H₂)/W₂

⇒ (24 × 10 × 9)/W₁ = (18 × D₂ × 6)/(2 × W₁)

⇒ (24 × 10 × 9 × 2 × W₁)/(18 × 6 × W₁)= D₂

⇒ D₂ = 40

∴ The time taken by 18 men to do 2 times of that work while working 6 hours per day is 40 days.