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The areas of three consecutive faces of a cuboid are 9 cm2, 25 cm2 and 36 cm2, then the volume (in cm2) of 
1. 60
2. 90
3. 3000
4. 100

1 Answer

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Correct Answer - Option 2 : 90

Given:

Areas of three consecutive faces of a cuboid = 9 cm2, 25 cm2 and 36 cm2

Formula used:

Volume = √Area1 × √Area2 × √Area3

Calculation:

Volume = √9 × √25 × √36 cm2

⇒ 3 × 5 × 6 cm2

⇒ 90 cm2

∴ The required volume of cuboid is 90 cm2

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