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An certain number of students from school X appeared in an examination and 30% students failed. 150% more students than those from school X, appeared in the same examination from school Y. If 80% of the total number of students who appeared from X and Y passed, then what is the percentage of students who failed from Y?
1. 24
2. 16
3. 20
4. 18

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Correct Answer - Option 2 : 16

Given:

Students failed in school X = 30%

Number of students in school Y = 150% more than number of students in school X

Students passed in both schools = 80%

Calculation:

Let number of students in school X be 100x

Number of failed students in school X = 30% of 100x

= 30x

Number of passes students in school Y = (100x – 30x)

= 70x

Number of students in school Y = 100x + 150% of 100x

= 100x + 150x = 250x

Total number of students in school X and school Y = 100x + 250x

= 350x

Number of passes students in both schools = 80% of 350x

= 280x

So, number of passed students in school Y = 280x – 70x

= 210x

Number of failed students in school Y = 250x –  210x

= 40x

Percentage of failed students in school Y = (40x/250x) × 100%

= 16%

∴ The percentage of students who failed from school Y is 16%

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