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If the current in the wire is doubled then the heat produce will become:
1. Half
2. One fourth
3. Double
4. Four times

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Best answer
Correct Answer - Option 4 : Four times

The correct answer is Four times.

Heating effect of current:

  • When the ends of a conductor are connected to a battery, then the free electrons move and the electric current flows through the wire.
  • These electrons collide continuously with the positive ions of the wire and thus the energy taken from the battery gets dissipated in the form of heat.
  • The effect of electric current due to which heat is produced in a wire when current is passed through it is called the heating effect of current.
  • The heat produced in the wire is,

⇒ H ∝ I2

⇒ H ∝ R

⇒ H ∝ t

\(⇒ H=\frac{I^2Rt}{J}\)

Where H = heat, I = current, R = resistance, t = time and J = Joule's equivalent

CALCULATION:

Given I2 = I1, R1 = R2 = R and t1 = t2 = t

  • When the current is I1,

\(⇒ H_{1}=\frac{I_{1}^{2}Rt}{J}\)     -----(1)

  • When the current is doubled,

\(⇒ H_{2}=\frac{I_{2}^{2}Rt}{J}\)

\(⇒ H_{2}=\frac{(2I_{1})^{2}Rt}{J}\)

\(⇒ H_{2}=\frac{4I_{1}^{2}Rt}{J}\)     -----(2)

By equation 1 and equation 2,

H2 = 4H

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