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A 400 W carrier is amplitude modulated with m = 0.75. The total power in AM is
1. 400 W
2. 512 W
3. 588 W
4. 650 W

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Correct Answer - Option 2 : 512 W

Concept:

The total transmitted power for an AM system is given by:

\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)

Pc = Carrier Power

μ = Modulation Index

Calculation:

Given:

Pc = 400 W, μ = 0.75

\({P_t} = 400\left( {1 + \frac{{{{0.75}^2}}}{2}} \right) \)

= 512.5 W

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