Correct Answer - Option 2 : 512 W

__Concept__:

The total transmitted power for an AM system is given by:

\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)

Pc = Carrier Power

μ = Modulation Index

__Calculation__:

Given:

Pc = 400 W, μ = 0.75

\({P_t} = 400\left( {1 + \frac{{{{0.75}^2}}}{2}} \right) \)

= 512.5 W