Correct Answer - Option 2 : 512 W
Concept:
The total transmitted power for an AM system is given by:
\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)
Pc = Carrier Power
μ = Modulation Index
Calculation:
Given:
Pc = 400 W, μ = 0.75
\({P_t} = 400\left( {1 + \frac{{{{0.75}^2}}}{2}} \right) \)
= 512.5 W
