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The diagonals of a parallelogram PQRS are along the lines x + 3y = 4 and 6x - 2y = 7. Then, PQRS must be a

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The diagonals of a parallelogram PQRS are along the lines x + 3y = 4 and 6x - 2y = 7. Then, PQRS must be a 

(a) rectangle 

(b) square

(c) cyclic quadrilateral 

(d) rhombus

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1 Answer

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Correct option: (d) rhombus

Explanation:

Slopeof line x + 3y = 4 is - 1/ 3

and slope of line 6x - 2y = 7 is 3.

Here,

Therefore, these two lines are perpendicular which show that both diagonals are perpendicular.

Hence, PQRS must be a rhombus.

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