Correct Answer - Option 1 : (x – 1)
Factors of (2x3 + x2 – 5x + 2)
⇒ (x - 1) (2x2 + 3x – 2)
⇒ (x – 1) (2x2 + 4x – x – 2)
⇒ (x - 1) [2x(x + 2) - 1(x + 2)]
⇒ (x -1) (2x -1) (x + 2)
Factors of (x 2 + 2x - 3)
⇒ x2 + 3x – x – 3
⇒ x(x + 3) -1(x + 3)
⇒ (x – 1) (x + 3)
(x - 1) is common in both the factors.
So, H.C.F is (x -1)