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If one of the angles of the triangle is 45° then find the angle formed by exterior angle bisectors of angle opposite of it?
1. 52.5°
2. 67.5°
3. 72.5°
4. 87.5°

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Correct Answer - Option 2 : 67.5°

Given:

The one of the angle of triangle is 45°

Formula Used:

In triangle ABC if OB and OC are the exterior angle bisector

∴ ∠BOC = 90 - ∠A/2

Calculation:

Let ABC is a triangle and let ∠A = 45° and OB and OC are the exterior angle bisector of triangle ABC

∴ ∠BOC = 90 - 45/2 = 67.5° 

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