Correct Answer - Option 3 : 12.5 MPa
Concept:
For thin cylindrical vessel:
Hoop stress, \({\sigma _h} = \frac{{pd}}{{2t}}\)
where p is internal pressure, d is the inner diameter of the cylinder, t is the thickness of the wall of the cylinder.
Calculation:
Given:
d = 50 mm, t = 2 mm, p = 1 MPa
\({\sigma _h} = \frac{{pd}}{{2t}} = \frac{{1 \times 50}}{{2 \times 2}} = 12.5~MPa\)
For thin cylindrical vessel:
Longitudinal stress, \({\sigma _L} = \frac{{pd}}{{4t}}\)
Volumetric strain, \({\epsilon_v} = \frac{{pd}}{{4tE}}\left( {5 - 4\mu } \right)\)
For thin spherical vessel:
Hoop stress/Longitudinal stress:
\({\sigma _h} = {\sigma _L} = \frac{{pd}}{{4t}}\)
Hoop strain/longitudinal strain:
\({\epsilon_L} = {\epsilon_h} = \frac{{pd}}{{4tE}}\left( {1 - \mu } \right)\)
Volumetric strain:
\({\epsilon_v} = 3{\epsilon_h} = \frac{{3pd}}{{4tE}}\left( {1 - \mu } \right)\)