Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
226 views
in General by (240k points)
closed by
The charge when C = 0.001 μF and V = 1 kV is 
1. 0.001 C
2. 1 μC
3. 1 C
4. None of these

1 Answer

0 votes
by (238k points)
selected by
 
Best answer
Correct Answer - Option 2 : 1 μC

Concept:

  • A capacitor is an electronic device that is used in an integrated circuit to store charges. 
  • And the amount of charge stored in a capacitor is given as

\(C = \frac{Q}{V}\)

Here,

Q = the amount of charge,

V = potential difference across capacitor and

C = capacitance of a given capacitor

Calculation:

Given: C = 0.001 μF and V = 1 kV

Q = CV = 0.001 × 10-6 × 1 × 103 = 1 μC

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...