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For the combination of resistance shown in figure, find the equivalent resistance between (a) C and D, (b) A and B

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a) Between C and D : 

The resistors R2, R3 and R4 are in series. They can be replaced by an equivalent resistance Rs where 

Rs = R2 + R3 + R4 = 3 + 3 + 3 = 9 Ω 

The resistance R5 and Rs are in parallel between the points C and D. 

The equivalent resistance between C and D then

Thus the equivalent resistance between C and D is 2.25 Ω. 

b) Between A and B : 

Now the resistors R1 , Rp and R6 are in series between the points a and B.

The equivalent resistance between A and B is 

RAB = R1 + Rp + R6 = 3 +2.25 + 3 = 8.25 Ω.

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