Correct Answer - Option 1 : Quantity I < Quantity II
Given:
Quantity I:
Time by which train 1 and train 2 will cross each other traveling in the same direction = 55 s
Time by which train 1 will cross the station master = 20 s
Length of train 1 and 2 = 220 m
Quantity II:
Time in which car crosses the train = 20 s
Length of train = 200 m
Speed of the car = 18 m/s
Concept used:
Speed, S = Distance/Time
The relative speed of two objects moving in the same direction = S1 – S2
Where ‘S’ is speed.
Calculation:
Quantity I:
Time taken to cross each other = 55 s = (2 × 220)/(ST1 – ST2)
⇒ ST1 – ST2 = 8 m/s
Time taken by train 1 to cross station master = 20 s = 220/ST1
⇒ ST1 = 11 m/s
Then, speed of train 2 = 11 – 8 = 3 m/s
Quantity I = 3 m/s
Quantity II:
Time taken by car to cross the train = 20 s = 200/(ST - 18)
⇒ Speed of the train, ST = 18 + 10 = 28 m/s
Quantity II = 28 m/s
Quantity I
|
Relation
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Quantity II
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3 m/s
|
<
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28 m/s
|
∴ From the table it is clear that, Quantity I < Quantity II.